Finding the Equation of a Line.

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1. Write the equation of the line with a slope of -2, passing through (4, 1) in standard form.


 y - 1 = 2(x - 4)
y = 2x - 9
 2x + y = 9

2. Write the equation of the line with a slope of onehalfand passing through (6,-5), in slope-intercept form.

 y + 5 = onehalf(x - 6)
  y = onehalfx - 8
  x - 2y = 16

3. Write the equation of the line with a slope of 0, passing through (7, -1).

  y = -1
  y = 7
  x = 7

4. Write the equation of the line with an undefined slope, passing through (7,-1).


 x = 7
 x = -1
 y = -1


5. Find the equation of the line passing through (-1, -5) and (-1, 4).  Hint:   Notice that the value of x does not change!

 x = -1
 x = -5
 x = 4

6. Find the equation of the line with a slope of 5 and a y-intercept of 4.  Put the equation in slope-intercept form.

 y = 4x + 5
 y = 5x + 4
 5x + 4y = 1

7. What is the slope and y-intercept of the line 2x - 3y = 6?

 m = 2/3 b = 6
 m = 2/3 b = -2
 m = -2/3 b = -2

8. What is the slope and y-intercept of the line 5x + 10y = 10?

m = -m = 1/2 b = 1
m = -m = 1/2 b = 1
m = 5  b = 10

9. Find the equation of the line parallel to the line 9x + 3y = 2 and passing through (1,1).

 y = 9x - 1
 y = -1/3x - 4
 y = 3x - 4

10. Find the equation of the line passing through (-5, -1) and perpendicular to the line 6x + 3y = 5.

 y = 1/2x + 3/2
 y = -2x + -11

y =  3/2x + 1/2

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Copyright © 2000 Donna Tupper.