How to Handle Significant Figures in Logarithm Dr. Yau
Outline of How to
Handle Sig.Fig. in Logarithm
If you want a complete review, click on each link below in order.
Brief Review of Logarithm
Logarithm of Numbers with
Exponents that are Integers
Antilog_of_Integers
Logarithm is the exponent to which a number is raised to produce a given number.
The common logarithm, commonly
abbreviated as log, refers to the exponent to which 10 has
to be raised, and the natural logarithm, abbreviated ln, refers to the exponent to which e
has to be raised. We will consider only the common logarithm here.
· For example, given the number 100, log of 100 is 2 since 10 has to be raised to a power of 2 to produce 100.
· In the case of log 0.01, the answer is – 2 since 0.01 = 10 –2 and we must raise 10 to the power of –2 to produce 0.01.
When we want to find the log of a number, we are asking what is x in 10x
to produce this number. See below for more examples.
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Logarithm of Numbers with Exponents that are Integers
Log of numbers with exponents that are integers (i.e., numbers that are simple powers of ten) do not require the use of calculators or log tables to compute. First express the number in exponential form, and the log of the number is simply the exponent.
See examples shown in the table below:
|
log 100 |
= log 10 2 |
= 2 |
|
log 10 |
= log 10 1 |
= 1 |
|
log 1 |
= log 10 0 |
= 0 |
|
log 0.1 |
= log 10 – 1 |
= –1 |
|
log 0.01 |
= log 10 – 2 |
= –2 |
|
log 0.00001 |
= log 10 –5 |
= –5 |
Note that when a number increases by powers of ten, such as from 10 to 100, the
logarithm of these numbers increase only by one unit (from 1 to 2). This is
referred to as a "logarithmic function". Certain measurements in
chemistry are related to each other by such logarithmic functions (e.g. %
transmittance vs. absorbance, H3O+ vs. pH).
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Antilog refers to the inverse function of log. It can also be written as log – 1 .
To find the antilog of a number, we simply reverse the process. It is the value equivalent to 10 brought to the power of the given number. In other words, antilog of 2 is 102 or 100. The antilog of –2 is 10 –2 or 0.01. Again, this does not require a calculator or a log table to compute.
See examples shown in the table below:
|
antilog 2 |
= 10 2 |
= 100 |
|
antilog 1 |
= 10 1 |
= 10 |
|
antilog 0 |
= 10 0 |
= 1 |
|
antilog – 1 |
= 10 – 1 |
= 0.1 |
|
antilog – 5 |
= 10 – 5 |
= 0.00001 |
Since the antilog function is the inverse of the log function,
the antilog of the log of a number is the number itself.
For example, antilog log 100 = 100.
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Logarithm of Numbers with Exponents that are Non-integers
Logarithm of more complex numbers require the use of a calculator or a log table. Only the use of a calculator will be discussed here.
If you had to calculate the log of a number, just
enter the number and then press log.
For example, to find log 2.5, enter 2.5 then press log. The answer is 0.397940009.
For
certain calculators, such as graphics calculators, you need to press log
first, followed by the open parenthesis sign ( ,
the number, the close parenthesis sign ) , and finally enter .
For such calculators, it is wise to get in the habit of always putting the
number within the parenthesis signs. In other words, to find log 2.5, it is
best to press log ( 2.5 ) enter .
Although it makes no difference in this case, it can cause trouble in other
situations if the parentheses were omitted. See below for example:
If you want to find log3x5, which has the answer 1.17609…, and you pressed log 3 x 5 enter , you would have computed (log 3) x 5 instead (giving you the answer of 2.3856…).
Especially if you are one of those who insist on entering numbers like 2x103 by pressing 2 x 10x 3 instead of the recommended keystrokes of 2 EE 3, you will have to think very carefully about the order of operation. The calculator will do the log function before multiplication and division. So, if you want to find log 2x103 (with the answer of 3.3010…) and pressed log 2 x 10x 3 enter , you would have computed for (log 2) x 103 instead (giving you the answer of 301.0299…) The problem is avoided by enclosing your number within the parentheses signs.
Practice by finding the log of the numbers in the table below:
|
log 4.2 |
0.62324929… |
|
log 4.2x102 |
2.62324929… |
|
log 4.2x105 |
5.62324929… |
|
log 4.2x10–1 |
–0.37675071… |
|
log 4.2x10–2 |
–1.37675071… |
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Significant Figures When Finding the Log of a Number
Before we begin, let us establish the vocabulary involving exponential expressions and logarithms:
In an exponential expression such as 4.2 x 10 – 2 , "4.2" is called the coefficient, and – 2 is called the exponent. Thus, 2 x 103 would have a coefficient of 2 and an exponent of 3.
The log of a number consists of two parts. The
number to the left of the decimal point is called the characteristic,
and the number to the right is the mantissa. Thus, the number
3.278 has a characteristic of 3 and a mantissa of
278. The number – 3.278 has a characteristic of – 3.
Let us examine the table again:
|
log 4.2 |
0.62324929… |
|
log 4.2x102 |
2.62324929… |
|
log 4.2x105 |
5.62324929… |
|
log 4.2x10–1 |
–0.37675071… |
|
log 4.2x10–2 |
–1.37675071… |
As you can see in the first three
examples in the table, the mantissa is established by the coefficient
(4.2) and the characteristic is established by the exponent.
In the last two examples, this may not be as apparent,
but log 4.2x10–1
is calculated as log
4.2 + log 10–1
which is equal to 0.6232… +
– 1
= – 0.37675071…
The point is, the significant figures of a number should be reflected only in the mantissa of its log! In other words, the number of significant figures of a number is the number of decimal places in its log.
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
CAUTION:
To figure out the number of decimal places, the number MUST be
first expressed in decimal form, rather than in exponential form!!!
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
For example, 4.2 has 2 sig. fig., so log 4.2 should have only 2 decimal places: 0.62
4.25 has
3 sig. fig., so log 4.25 should have 3 decimal places: 0.628
0.03 has 1 sig. fig., so log 0.03 should have 1 decimal place: -1.5
1.01 has 3 sig. fig., so log 1.01 should have 3 decimal places: 4x10-3
= 0.004
Practice with the examples below:
|
log 4.2 |
0.62 |
|
log 4.2x102 |
2.62 |
|
log 4.2x105 |
5.62 |
|
log 4.2x10–1 |
–0.37 |
|
log 0.002735 |
–2.5630 |
|
log 3200 |
3.50 |
|
log 50000 |
4.7 |
|
log 1.002 |
9x10-4 |
If you had trouble with the last 4
examples, you need to review the rules for significant figures.
Click here to review the rules for significant
figures.
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Determining the Antilog of Numbers that are Non-integers.
Again, either a calculator or a log table is required. Only the use of a calculator will be discussed here.
If you have to find the antilog of 3.5, simply enter 3.5 then press the 10 x key. Generally the log and the 10 x functions share the same key, but involves pressing either the 2nd key, the SHIFT key or the INVERSE key first.
With the graphics calculator, you would press the 10 x key first before entering the number. Again, it would be wise to always make use of the parenthesis signs.
Practice with the following examples:
|
antilog 3.5 |
3162.27766… |
|
antilog 0.35 |
2.238721139… |
|
antilog – 3.5 |
3.16227…x104 |
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Significant Figures When Finding the Antilog of a Number
You just need to reverse your thinking. The number of decimal places in the number determines the number of significant figures in it antilog. Start by examining the table under the heading "Significant Figures When Finding the Log of a Number", and note that the number of decimal places in the second column corresponds to the number of significant figures in the left column.
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
CAUTION:
To figure out the number of decimal places, remember to convert the
number into decimal form first, rather than counting the decimal places while
it is still in exponential form. For example, 2.15 x 10–1 has 3 decimal
places not 2, since we are really considering 0.215.
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Now practice with the examples below:
|
antilog 2.78 |
6.0x102 |
|
antilog 12.275 |
1.88x1012 |
|
antilog – 3.8 |
2x10–4 |
|
antilog 15 |
1015 |
|
antilog 1.23x10–2 |
1.029 |
|
antilog 3x10–4 |
1.001 |
|
antilog 9.6x10–3 |
1.022 |
If you had trouble with the last 3 examples, you probably forgot that the numbers in the first column have to be converted into decimal form before you count the number of decimal places. Thus, 1.23 x 10–2 is equivalent to 0.0123, which has 4 decimal places, and its antilog should have 4 significant figures (1.029).
In the case of the antilog of 15 (which has no decimal places), the answer has no significant figures, as indicated by merely 1015.
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How to Solve Simple Equations Involving Logarithms
Given the equation log x = 7.82, you would first find the antilog of both
sides of the equation:
antilog log x = antilog 7.82
x = antilog 7.82
= 6.606934…x107
= 6.6x107 (Ans. has 2 sig.fig.)
Given the equation log 5.42 x 10–2 = x, you would simply find the
log of the number:
– 1.266 = x. (Ans. has 3 decimal places)
Practice with the following examples:
|
log x = 4.28 x 10–2 |
x = 1.104 (Remember to find x you need to find the antilog of 4.28x10-2 , which is 0.0428 and has 4 decimal places. Ans. should have 4 sig.fig.) |
|
|
log x = 0.14 x 10–1 |
x = 1.03 (3 sig.fig. because 0.14x10-1 has 3 decimal places.) |
|
|
log 0.053 = x |
x = 1.28 (2 decimal places) |
|
|
log 104.3 = x |
x = 4.3 (review definition of log) |
|
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To find the log of a number:
1. Enter the number then press LOG.
For graphics calculators,
press LOG (
the number ) ENTER
2. Express the answer in decimal form.
3. The number of sig. fig. in the original number is the number of decimal places in the answer.
Quick check: log 7.6x10–3 = – 2.119186 = – 2.12
To find the antilog of a number:
1. Enter the number then press 10x .
For graphics calculators,
press 10 x
( the number )
ENTER .
2. Convert the original number to decimal form and count the number of decimal places.
3. The number of decimal places is the number of sig. fig. in the answer.
Quick check: if log x = – 6.2x10–1
then x = antilog – 6.2x10–1 = 2.398832x10–1 = 2.4x10–1
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APPLICATIONS TO CHEMISTRY PROBLEMS
1. Percent transmittance (%T) is related to the absorbance (A) by the equation: A = - log (%T/100).
a) Calculate A if %T is 72.9.
Try to work out this problem, giving the answer to the correct sig. fig. before looking at the answer and the solution below.
Answer: Absorbance is 0.137
Solution: A = - log (72.9/100)
= - log 0.729
= - (- 0.13727272...)
= 0.137 (3 decimal places because 72.9 has 3 sig. fig.)
b) Calculate A if %T is 31.6.
Try to work out this problem, giving the answer to the correct sig. fig. before looking at the answer and the solution below.
Answer: Absorbance is 0.500
Solution: A = - log (31.6/100)
= - log 0.316
= - (- 0.500312917...)
= 0.500 (3 decimal places)
c) Calculate %T if the absorbance is 0.931
Try to work out this
problem, giving the answer to the correct sig. fig. before looking at
the answer and the solution below.
Answer: Percent transmittance is 11.7%
Solution: 0.931 = - log (%T/100)
- 0.931 = log (%T/100)
[Get rid of the log function by finding antilog of both sides.]
antilog - 0.931 = antilog log (%T/100)
0.117219...=
(%T/100)
[Get rid of 100 by multiplying both sides by 100.]
11.7
= %T
d) Calculate %T if the absorbance is 0.27
Try to work out this problem, giving the answer to the correct sig. fig. before looking at the answer and the solution below.
Answer: Percent transmittance is 54%
Solution: 0.27 = - log
(%T/100)
- 0.27 = log (%T/100)
antilog - 0.27 = antilog log
(%T/100)
5.37031...x10-1= %T/100
54 = %T
2. The hydronium ion concentration ([H3O+]) of a solution is related to the pH of the solution by the equation:
pH = - log [H3O+]
a) If the [H3O+] is 3.8 x 10-2 M, what is the pH of the solution?
Try to work out this problem, giving the answer to the correct sig. fig. before looking at the answer and the solution below.
Answer: The pH is 1.42
Solution: pH = - log 3.8 x 10-2
= - (-1.420216...)
[3.8 has 2 sig.fig. Thus its log should have 2
decimal places.]
= 1.42
b) If the [H3O+] is 7.2 x
10-12 M, what is the pH of the solution?
Try to work out this problem, giving the answer to the correct sig. fig. before looking at the answer and the solution below.
Answer: The pH is 11.14
Solution: pH = - log 7.2 x 10-12
= - (- 1.11426...x101)
=
11.14
[7.2 has 2 sig.fig. Thus its log should have 2 decimal places.]
c) If the pH is 10.3, what is the [H3O+] in the solution?
Try to work out this problem, giving the answer to the correct sig. fig. before looking at the answer and the solution below.
Answer: The hydronium ion concentration is 5 x 10-11
Solution: 10.3 = - log [H3O+]
- 10.3 = log [H3O+]
antilog - 10.3 = antilog log [H3O+]
5.01187...x10-11= [H3O+]
[10.3 has one decimal place. Thus its antilog has one sig.fig.]
5
x 10-11=[H3O+]
d) If the pH is 2.52, what is the [H3O+]
in the solution?
Try to work out this
problem, giving the answer to the correct sig. fig. before looking at
the answer and the solution below.
Answer: [H3O+] is 3.0x10-3M
Solution: 2.52 = - log [H3O+]
- 2.52 = log [H3O+]
antilog -2.52 = [H3O+]
3.01995...x10-3= [H3O+]
3.0x10-3=[H3O+]
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